(2x^2+13x+23)/(x+3)

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Solution for (2x^2+13x+23)/(x+3) equation: 


D( x )

x+3 = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:+oo)

(2*x^2+13*x+23)/(x+3) = 0

2*x^2+13*x+23 = 0

2*x^2+13*x+23 = 0

DELTA = 13^2-(2*4*23)

DELTA = -15

DELTA < 0

1 = 0

1/(x+3) = 0

x belongs to the empty set

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